Post-of-the-month results - September 2011

kevinchess1
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Re: Post-of-the-month results - September 2011

Post by kevinchess1 » Mon Oct 03 2011 2:26pm

Luke_PieStalker wrote:Well done winners.

Educate me - What is the 'award' given the the also rans in the list. As in 4th,5th,6th etc?
2 words, last one's ...awl
Politically incorrect since 69

richard@imutual
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Re: Post-of-the-month results - September 2011

Post by richard@imutual » Mon Oct 03 2011 2:28pm

It's just the link I use for awarding shares to the winners - see viewtopic.php?p=11790#p11790

1960mackem
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Re: Post-of-the-month results - September 2011

Post by 1960mackem » Mon Oct 03 2011 2:29pm

kevinchess1 wrote:
Luke_PieStalker wrote:Well done winners.

Educate me - What is the 'award' given the the also rans in the list. As in 4th,5th,6th etc?
2 words, last one's ...awl

Footb...... :thumbup:
Thanked by: kevinchess1

mark_r_abcd
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Re: Post-of-the-month results - September 2011

Post by mark_r_abcd » Mon Oct 03 2011 4:08pm

Mel wrote:One thought that comes to mind is to use an equation of number of thankers multiplied by their shareholding.
Isn't that how it currently works?

How about using the thanks system like now to generate a shortlist of maybe half a dozen posts, then using a simple poll to pick the winners?

richard@imutual
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Re: Post-of-the-month results - September 2011

Post by richard@imutual » Mon Oct 03 2011 4:18pm

Could do. Apart from taking longer though, there is also a danger that the poll would be representative because only a small number of members would bother to vote. Using a month's worth of 'thanking' to determine the winners, rather than just to produce a shortlist, ensures you get a wider view.
mark_r_abcd wrote:
Mel wrote:One thought that comes to mind is to use an equation of number of thankers multiplied by their shareholding.
Isn't that how it currently works?
I think what Mel means is explained by the following example:
5 people vote for a post. 4 of them have 100 shares and 1 of them has 5000 shares. The total shares (for the purpose of potm) would be (4+1)*(100+100+100+100+5000) = 5 *5400 = 27000

Am I right, Mel?

Bruce
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Re: Post-of-the-month results - September 2011

Post by Bruce » Mon Oct 03 2011 5:16pm

Simple solution: everyone should earn more shares, so that they can compete with Bruce :lol:

Mel
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Re: Post-of-the-month results - September 2011

Post by Mel » Mon Oct 03 2011 6:48pm

richard@imutual wrote:Could do. Apart from taking longer though, there is also a danger that the poll would be representative because only a small number of members would bother to vote. Using a month's worth of 'thanking' to determine the winners, rather than just to produce a shortlist, ensures you get a wider view.
mark_r_abcd wrote:
Mel wrote:One thought that comes to mind is to use an equation of number of thankers multiplied by their shareholding.
Isn't that how it currently works?
I think what Mel means is explained by the following example:
5 people vote for a post. 4 of them have 100 shares and 1 of them has 5000 shares. The total shares (for the purpose of potm) would be (4+1)*(100+100+100+100+5000) = 5 *5400 = 27000

Am I right, Mel?
Correct. :clap: I knew I could rely on Richard to understand. :thumbup:

rayf
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Re: Post-of-the-month results - September 2011

Post by rayf » Mon Oct 03 2011 7:15pm

congrats to the winners!!

adamred6
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Re: Post-of-the-month results - September 2011

Post by adamred6 » Tue Oct 04 2011 9:00am

well done to you three and your very good posts

bobster007
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Re: Post-of-the-month results - September 2011

Post by bobster007 » Tue Oct 04 2011 11:10am

1960mackem wrote:What other measurement tools have you got to give a fair outcome ?
Just my two cents worth.

How about using a random generator such as the http://www.random.org/integers/ to pick the winners from the selected posts.

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